What is the answer to e^{-2ln(x)}=ln(x^{-2}) ?

The answer to e^{-2ln(x)}=ln(x^{-2}) is No Solution for x\in\mathbb{R}

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e^{-2ln(x)}=ln(x^{-2})

e^{- 2 l n (x)} = ln (x^{- 2})

No Solution for x \in R

Solution steps

e^{- 2 l n (x)} = ln (x^{- 2})

Apply log rules

e^{- 2 l n (x)} = (- 2) ln (x)

Rewrite the equation with

ln (x) = u

e^{- 2 u} = (- 2) u

Solve

e^{- 2 u} = (- 2) u :

No Solution for

u \in R

No Solution for x \in R

lo g_{10} (x) = 1.46

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lo g_{10} (x) = 1 + lo g_{3} (x)

What is the answer to e^{-2ln(x)}=ln(x^{-2}) ?
The answer to e^{-2ln(x)}=ln(x^{-2}) is No Solution for x\in\mathbb{R}