What is the answer to 5=log_{10}(2x)-log_{10}(x+1) ?

The answer to 5=log_{10}(2x)-log_{10}(x+1) is No Solution for x\in\mathbb{R}

Solve for x: 5=log_{10}(2x)-log_{10}(x+1)

The solution is No Solution for x\in\mathbb{R}

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5 = lo g_{10} (2 x) - lo g_{10} (x + 1)

No Solution for x \in R

Solution steps

5 = lo g_{10} (2 x) - lo g_{10} (x + 1)

Add

lo g_{10} (x + 1)

to both sides

5 + lo g_{10} (x + 1) = lo g_{10} (2 x) - lo g_{10} (x + 1) + lo g_{10} (x + 1)

Simplify

5 + lo g_{10} (x + 1) = lo g_{10} (2 x)

Apply log rules

100000 (x + 1) = 2 x

Solve

100000 (x + 1) = 2 x : x = - \frac{50000}{49999}

x = - \frac{50000}{49999}

Verify Solutions:

x = - \frac{50000}{49999}

False

The solution is

No Solution for x \in R

0.2 = - lo g_{10} (x)

lo g_{2} (11 - x) = lo g_{2} (x + 1) + 3

lo g_{a} (N) = ln (x)

lo g_{3} (2 x) = 1

lo g_{x} (2 x + 1) = - 1

What is the answer to 5=log_{10}(2x)-log_{10}(x+1) ?
The answer to 5=log_{10}(2x)-log_{10}(x+1) is No Solution for x\in\mathbb{R}
Solve for x: 5=log_{10}(2x)-log_{10}(x+1)
The solution is No Solution for x\in\mathbb{R}