What is the answer to ln(x+15)-ln(3-2x)=4ln(2) ?

The answer to ln(x+15)-ln(3-2x)=4ln(2) is x=1

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ln(x+15)-ln(3-2x)=4ln(2)

ln (x + 15) - ln (3 - 2 x) = 4 ln (2)

x = 1

Solution steps

ln (x + 15) - ln (3 - 2 x) = 4 ln (2)

Add

ln (3 - 2 x)

to both sides

ln (x + 15) - ln (3 - 2 x) + ln (3 - 2 x) = 4 ln (2) + ln (3 - 2 x)

Simplify

ln (x + 15) = 4 ln (2) + ln (3 - 2 x)

Apply log rules

x + 15 = 16 (3 - 2 x)

Solve

x + 15 = 16 (3 - 2 x) : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

a ln (2) = \frac{a}{4} ln (a)

lo g_{10} (9 x + 1) = 3

lo g_{32} (4) = lo g_{2} (x)

lo g_{3} (x) = \frac{3}{2}

lo g_{16} (X) = \frac{3}{4}

What is the answer to ln(x+15)-ln(3-2x)=4ln(2) ?
The answer to ln(x+15)-ln(3-2x)=4ln(2) is x=1
Solve for x: ln(x+15)-ln(3-2x)=4ln(2)
The solution is x=1