What is the answer to log_{6}(x+1)+log_{6}(2)=2 ?

The answer to log_{6}(x+1)+log_{6}(2)=2 is x=17

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log_{6}(x+1)+log_{6}(2)=2

lo g_{6} (x + 1) + lo g_{6} (2) = 2

x = 17

Solution steps

lo g_{6} (x + 1) + lo g_{6} (2) = 2

Move

lo g_{6} (2)

to the right side

lo g_{6} (x + 1) = 2 - lo g_{6} (2)

Apply log rules

x + 1 = 18

Solve

x + 1 = 18 : x = 17

x = 17

Verify Solutions:

x = 17

True

The solution is

x = 17

2 + ln (x + 5) = 7

a (t) lo g_{10} (t) = a (t) y

2.38 = - lo g_{10} (x)

lo g_{10} (x) + lo g_{10} (x + 5) = 4

lo g_{10} (x) = 11.2

What is the answer to log_{6}(x+1)+log_{6}(2)=2 ?
The answer to log_{6}(x+1)+log_{6}(2)=2 is x=17
Solve for x: log_{6}(x+1)+log_{6}(2)=2
The solution is x=17