What is the answer to 2ln(x)-ln(x^2+x-3)=0 ?

The answer to 2ln(x)-ln(x^2+x-3)=0 is x=3

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2ln(x)-ln(x^2+x-3)=0

2 ln (x) - ln (x^{2} + x - 3) = 0

x = 3

Solution steps

2 ln (x) - ln (x^{2} + x - 3) = 0

Apply log rules

x^{2} = x^{2} + x - 3

Solve

x^{2} = x^{2} + x - 3 : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

lo g_{4} (x - 6) + lo g_{4} (2) = 2

lo g_{2} (x + 5) = 4

lo g_{8} (x) = \frac{- 2}{3}

ln (x) + ln (x - 6) = ln (7 x)

lo g_{5} (x) = 1 + lo g_{5} (x - 4)

What is the answer to 2ln(x)-ln(x^2+x-3)=0 ?
The answer to 2ln(x)-ln(x^2+x-3)=0 is x=3
Solve for x: 2ln(x)-ln(x^2+x-3)=0
The solution is x=3