What is the answer to ln(x+3)+ln(x-1)=ln(4x+12) ?

The answer to ln(x+3)+ln(x-1)=ln(4x+12) is x=5

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ln(x+3)+ln(x-1)=ln(4x+12)

ln (x + 3) + ln (x - 1) = ln (4 x + 12)

x = 5

Solution steps

ln (x + 3) + ln (x - 1) = ln (4 x + 12)

Apply log rules

(x + 3) (x - 1) = 4 x + 12

Solve

(x + 3) (x - 1) = 4 x + 12 : x = 5, x = - 3

x = 5, x = - 3

Verify Solutions:

x = 5

True

, x = - 3

False

The solution is

x = 5

lo g_{10} (x) = 5.833

lo g_{3} (x + 2) + lo g_{3} (x + 5) = 1

lo g_{4} (x + 2) = lo g_{4} (8)

lo g_{3} (5 x - 1) = 2

ln (x + 3) - ln (5 - 4 x) = 2 ln (2)

What is the answer to ln(x+3)+ln(x-1)=ln(4x+12) ?
The answer to ln(x+3)+ln(x-1)=ln(4x+12) is x=5
Solve for x: ln(x+3)+ln(x-1)=ln(4x+12)
The solution is x=5