What is the answer to log_{3}(x+2)+log_{3}(x+5)=1 ?

The answer to log_{3}(x+2)+log_{3}(x+5)=1 is x=(-7+sqrt(21))/2

Solve for x: log_{3}(x+2)+log_{3}(x+5)=1

The solution is x=(-7+sqrt(21))/2

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lo g_{3} (x + 2) + lo g_{3} (x + 5) = 1

x = \frac{- 7 + 21}{2}

Decimal Notation

x = - 1.20871 \dots

Solution steps

lo g_{3} (x + 2) + lo g_{3} (x + 5) = 1

Apply log rules

(x + 2) (x + 5) = 3

Solve

(x + 2) (x + 5) = 3 : x = \frac{- 7 + 21}{2}, x = \frac{- 7 - 21}{2}

x = \frac{- 7 + 21}{2}, x = \frac{- 7 - 21}{2}

Verify Solutions:

x = \frac{- 7 + 21}{2}

True

, x = \frac{- 7 - 21}{2}

False

The solution is

x = \frac{- 7 + 21}{2}

lo g_{4} (x + 2) = lo g_{4} (8)

lo g_{3} (5 x - 1) = 2

ln (x + 3) - ln (5 - 4 x) = 2 ln (2)

lo g_{5} (x - 1) = 2 + 2 lo g_{5} (x - 3)

4 + lo g_{2} (9 k) = 2

What is the answer to log_{3}(x+2)+log_{3}(x+5)=1 ?
The answer to log_{3}(x+2)+log_{3}(x+5)=1 is x=(-7+sqrt(21))/2
Solve for x: log_{3}(x+2)+log_{3}(x+5)=1
The solution is x=(-7+sqrt(21))/2