What is the answer to log_{2x^2}(x^3+x)=1 ?

The answer to log_{2x^2}(x^3+x)=1 is x=1

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log_{2x^2}(x^3+x)=1

lo g_{2 x^{2}} (x^{3} + x) = 1

x = 1

Solution steps

lo g_{2 x^{2}} (x^{3} + x) = 1

Apply log rules

\frac{ln ( x ^{3} + x )}{ln ( 2 x ^{2} )} = 1

Multiply both sides by

ln (2 x^{2})

\frac{ln ( x ^{3} + x )}{ln ( 2 x ^{2} )} ln (2 x^{2}) = 1 \cdot ln (2 x^{2})

Simplify

ln (x^{3} + x) = ln (2 x^{2})

Apply log rules

x^{3} + x = 2 x^{2}

Solve

x^{3} + x = 2 x^{2} : x = 0, x = 1

x = 0, x = 1

Verify Solutions:

x = 0

False

, x = 1

True

The solution is

x = 1

10 = ln (x)

5000 \cdot lo g_{2} (n) = n

lo g_{2} (2 x + 2) = 2

lo g_{10} (x) = 18.96

lo g_{10} (4) - 3 lo g_{10} (x + 5) = 3

What is the answer to log_{2x^2}(x^3+x)=1 ?
The answer to log_{2x^2}(x^3+x)=1 is x=1
Solve for x: log_{2x^2}(x^3+x)=1
The solution is x=1