What is the answer to log_{10}(4)-3log_{10}(x+5)=3 ?

The answer to log_{10}(4)-3log_{10}(x+5)=3 is x= 1/(10^{(3-2log_{10)(2))/3}}-5

Solve for x: log_{10}(4)-3log_{10}(x+5)=3

The solution is x= 1/(10^{(3-2log_{10)(2))/3}}-5

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lo g_{10} (4) - 3 lo g_{10} (x + 5) = 3

x = \frac{1}{1 0 ^{\frac{3 - 2 l o g _{10} ( 2 )}{3}}} - 5

Solution steps

lo g_{10} (4) - 3 lo g_{10} (x + 5) = 3

Move

lo g_{10} (4)

to the right side

- 3 lo g_{10} (x + 5) = 3 - lo g_{10} (4)

Divide both sides by

- 3

lo g_{10} (x + 5) = - \frac{3 - lo g _{10} ( 4 )}{3}

Apply log rules

x + 5 = \frac{1}{1 0 ^{\frac{3 - 2 l o g _{10} ( 2 )}{3}}}

Solve

x + 5 = \frac{1}{1 0 ^{\frac{3 - 2 l o g _{10} ( 2 )}{3}}} : x = \frac{1}{1 0 ^{\frac{3 - 2 l o g _{10} ( 2 )}{3}}} - 5

x = \frac{1}{1 0 ^{\frac{3 - 2 l o g _{10} ( 2 )}{3}}} - 5

Verify Solutions:

x = \frac{1}{1 0 ^{\frac{3 - 2 l o g _{10} ( 2 )}{3}}} - 5

True

The solution is

x = \frac{1}{1 0 ^{\frac{3 - 2 l o g _{10} ( 2 )}{3}}} - 5

ln (x) = 2.0706

2 lo g_{5} (x) = lo g_{x} (25)

lo g_{3} (2 x - 2) = lo g_{3} (x + 10)

lo g_{3} (4 x - 1) = 4

e \cdot ln (x - 10) = e \cdot ln (8)

What is the answer to log_{10}(4)-3log_{10}(x+5)=3 ?
The answer to log_{10}(4)-3log_{10}(x+5)=3 is x= 1/(10^{(3-2log_{10)(2))/3}}-5
Solve for x: log_{10}(4)-3log_{10}(x+5)=3
The solution is x= 1/(10^{(3-2log_{10)(2))/3}}-5