What is the answer to -2log_{4}(-2x+3)-5=5 ?

The answer to -2log_{4}(-2x+3)-5=5 is x= 3071/2048

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-2log_{4}(-2x+3)-5=5

- 2 lo g_{4} (- 2 x + 3) - 5 = 5

x = \frac{3071}{2048}

Solution steps

- 2 lo g_{4} (- 2 x + 3) - 5 = 5

Move

5

to the right side

- 2 lo g_{4} (- 2 x + 3) = 10

Divide both sides by

- 2

lo g_{4} (- 2 x + 3) = - 5

Apply log rules

- 2 x + 3 = \frac{1}{1024}

Solve

- 2 x + 3 = \frac{1}{1024} : x = \frac{3071}{2048}

x = \frac{3071}{2048}

Verify Solutions:

x = \frac{3071}{2048}

True

The solution is

x = \frac{3071}{2048}

10 lo g_{10} (x) = 36.3

lo g_{10} (2 x - 3) = - 1

2 lo g_{4} (64) = 3 lo g_{4} (x)

y, x = 1 - 3 ln (2 - 3 y)

lo g_{6} (a) = 19

What is the answer to -2log_{4}(-2x+3)-5=5 ?
The answer to -2log_{4}(-2x+3)-5=5 is x= 3071/2048
Solve for x: -2log_{4}(-2x+3)-5=5
The solution is x= 3071/2048