What is the answer to log_{10}(2x-3)=-1 ?

The answer to log_{10}(2x-3)=-1 is x= 31/20

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log_{10}(2x-3)=-1

lo g_{10} (2 x - 3) = - 1

x = \frac{31}{20}

Solution steps

lo g_{10} (2 x - 3) = - 1

Apply log rules

2 x - 3 = \frac{1}{10}

Solve

2 x - 3 = \frac{1}{10} : x = \frac{31}{20}

x = \frac{31}{20}

2 lo g_{4} (64) = 3 lo g_{4} (x)

y, x = 1 - 3 ln (2 - 3 y)

lo g_{6} (a) = 19

lo g_{10} (3 x - 2) + lo g_{10} (x) = 0

ln (2 x + 2) - 1 = ln (x - 1)

What is the answer to log_{10}(2x-3)=-1 ?
The answer to log_{10}(2x-3)=-1 is x= 31/20
Solve for x: log_{10}(2x-3)=-1
The solution is x= 31/20