What is the answer to 4=ln(7/(7+x)) ?

The answer to 4=ln(7/(7+x)) is x= 7/(e^4)-7

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4=ln(7/(7+x))

4 = ln (\frac{7}{7 + x})

x = \frac{7}{e ^{4}} - 7

Solution steps

4 = ln (\frac{7}{7 + x})

Apply log rules

e^{4} = \frac{7}{7 + x}

Multiply both sides by

7 + x

e^{4} (7 + x) = \frac{7}{7 + x} (7 + x)

Simplify

e^{4} (7 + x) = 7

Solve

e^{4} (7 + x) = 7 : x = \frac{7}{e ^{4}} - 7

x = \frac{7}{e ^{4}} - 7

Verify Solutions:

x = \frac{7}{e ^{4}} - 7

True

The solution is

x = \frac{7}{e ^{4}} - 7

lo g_{10} (\frac{1}{x}) = 7.22

5 lo g_{4} (x - 2) - 16 = - 16

lo g_{10} (\frac{1}{x}) = 7.87

x, 0.67 = lo g_{10} (x)

(ln (x))^{2} = 3 ln (x) - 2

What is the answer to 4=ln(7/(7+x)) ?
The answer to 4=ln(7/(7+x)) is x= 7/(e^4)-7
Solve for x: 4=ln(7/(7+x))
The solution is x= 7/(e^4)-7