What is the answer to log_{10}(x^{81})=4 ?

The answer to log_{10}(x^{81})=4 is x=10^{4/81}

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log_{10}(x^{81})=4

lo g_{10} (x^{81}) = 4

x = 1 0^{\frac{4}{81}}

Solution steps

lo g_{10} (x^{81}) = 4

Apply log rules

x = 1 0^{\frac{4}{81}}

Verify Solutions:

x = 1 0^{\frac{4}{81}}

True

The solution is

x = 1 0^{\frac{4}{81}}

lo g_{e} (x) = - 1

lo g_{5} (5 x^{2}) - lo g_{5} (4) = 5

ln (x + 2) - ln (x) = 4

lo g_{a} (a) = 2

lo g_{y} (2) = 8

What is the answer to log_{10}(x^{81})=4 ?
The answer to log_{10}(x^{81})=4 is x=10^{4/81}
Solve for x: log_{10}(x^{81})=4
The solution is x=10^{4/81}