What is the answer to ln(9x)+3=ln(3x+2) ?

The answer to ln(9x)+3=ln(3x+2) is x= 2/(3(3e^3-1))

Solve for x: ln(9x)+3=ln(3x+2)

The solution is x= 2/(3(3e^3-1))

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ln (9 x) + 3 = ln (3 x + 2)

x = \frac{2}{3 ( 3 e ^{3} - 1 )}

Decimal Notation

x = 0.01125 \dots

Solution steps

ln (9 x) + 3 = ln (3 x + 2)

Apply log rules

9 x e^{3} = 3 x + 2

Solve

9 x e^{3} = 3 x + 2 : x = \frac{2}{3 ( 3 e ^{3} - 1 )}

x = \frac{2}{3 ( 3 e ^{3} - 1 )}

Verify Solutions:

x = \frac{2}{3 ( 3 e ^{3} - 1 )}

True

The solution is

x = \frac{2}{3 ( 3 e ^{3} - 1 )}

lo g_{a} (4) = 1.585

4 = ln (5 x + e) - 1

lo g_{10} (3 x + 2) = lo g_{10} (x - 1)

lo g_{3} (8 x) - 4 lo g_{3} (2) = 0

lo g_{2} (x - 5) - lo g_{2} (x + 5) = 5

What is the answer to ln(9x)+3=ln(3x+2) ?
The answer to ln(9x)+3=ln(3x+2) is x= 2/(3(3e^3-1))
Solve for x: ln(9x)+3=ln(3x+2)
The solution is x= 2/(3(3e^3-1))