What is the answer to solvefor x,fx=log_{10}(x-3) ?

The answer to solvefor x,fx=log_{10}(x-3) is x=-(\W(-ln(10)*1000^ff)-3ln(10)f)/(ln(10)f)

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solvefor x,fx=log_{10}(x-3)

solve for

x, f x = lo g_{10} (x - 3)

x = - \frac{W ( - ln ( 10 ) \cdot 100 0 ^{f} f ) - 3 ln ( 10 ) f}{ln ( 10 ) f}

Solution steps

f x = lo g_{10} (x - 3)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{f x} = 1 0^{l o g_{10} (x - 3)}

Simplify

1 0^{l o g_{10} (x - 3)} : x - 3

1 0^{f x} = x - 3

Solve

1 0^{f x} = x - 3 : x = - \frac{W ( - ln ( 10 ) \cdot 100 0 ^{f} f ) - 3 ln ( 10 ) f}{ln ( 10 ) f}

x = - \frac{W ( - ln ( 10 ) \cdot 100 0 ^{f} f ) - 3 ln ( 10 ) f}{ln ( 10 ) f}

Verify Solutions:

x = - \frac{W ( - ln ( 10 ) \cdot 100 0 ^{f} f ) - 3 ln ( 10 ) f}{ln ( 10 ) f}

True

The solution is

x = - \frac{W ( - ln ( 10 ) \cdot 100 0 ^{f} f ) - 3 ln ( 10 ) f}{ln ( 10 ) f}

lo g_{10} (6 - 2 x) = 1 + lo g_{10} (x)

y, x = 2 lo g_{10} (y)

lo g_{10} (p^{- 1}) = 1

lo g_{3} (x) + 3 = 2

7.5 = 0.65 lo g_{10} (0 E) + 1.45

What is the answer to solvefor x,fx=log_{10}(x-3) ?
The answer to solvefor x,fx=log_{10}(x-3) is x=-(\W(-ln(10)*1000^ff)-3ln(10)f)/(ln(10)f)