What is the answer to log_{10}(p^{-1})=1 ?

The answer to log_{10}(p^{-1})=1 is p= 1/10

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log_{10}(p^{-1})=1

lo g_{10} (p^{- 1}) = 1

p = \frac{1}{10}

Solution steps

lo g_{10} (p^{- 1}) = 1

Apply log rules

\frac{1}{p} = 10

Solve

\frac{1}{p} = 10 : p = \frac{1}{10}

p = \frac{1}{10}

lo g_{3} (x) + 3 = 2

7.5 = 0.65 lo g_{10} (0 E) + 1.45

lo g_{10} (X) = 3.4146

a, a^{b} = e^{b l n (a)}

ln (x) = 7.352205355

What is the answer to log_{10}(p^{-1})=1 ?
The answer to log_{10}(p^{-1})=1 is p= 1/10
Solve for p: log_{10}(p^{-1})=1
The solution is p= 1/10