What is the answer to solvefor a,a^b=e^{bln(a)} ?

The answer to solvefor a,a^b=e^{bln(a)} is a>0

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solvefor a,a^b=e^{bln(a)}

solve for

a, a^{b} = e^{b l n (a)}

a > 0

Solution steps

a^{b} = e^{b l n (a)}

Apply log rules

b ln (a) = b ln (a)

Rewrite the equation with

ln (a) = u

b u = b u

Both sides are equal

True for all u

Verify Solutions:

a > 0

The solution is

a > 0

ln (x) = 7.352205355

lo g_{2} (x) = 3 - lo g_{2} (3 x - 10)

lo g_{e} (\frac{760}{x}) = 751

lo g_{4} (x^{2} + 3) = 2

lo g_{b} (343) = - \frac{3}{2}

What is the answer to solvefor a,a^b=e^{bln(a)} ?
The answer to solvefor a,a^b=e^{bln(a)} is a>0