What is the answer to log_{4}(x^2+3)=2 ?

The answer to log_{4}(x^2+3)=2 is x=sqrt(13),x=-sqrt(13)

Solve for x: log_{4}(x^2+3)=2

The solution is x=sqrt(13),x=-sqrt(13)

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lo g_{4} (x^{2} + 3) = 2

x = 13, x = - 13

Decimal Notation

x = 3.60555 \dots, x = - 3.60555 \dots

Solution steps

lo g_{4} (x^{2} + 3) = 2

Apply log rules

x^{2} + 3 = 16

Solve

x^{2} + 3 = 16 : x = 13, x = - 13

x = 13, x = - 13

lo g_{b} (343) = - \frac{3}{2}

lo g_{a} (64) = 2

lo g_{9} (2 x - 7) = \frac{3}{2}

3 lo g_{8} (x) - lo g_{x} (64 + 1) = 0

lo g_{4} (x + 2) + lo g_{4} (x - 4) = 2

What is the answer to log_{4}(x^2+3)=2 ?
The answer to log_{4}(x^2+3)=2 is x=sqrt(13),x=-sqrt(13)
Solve for x: log_{4}(x^2+3)=2
The solution is x=sqrt(13),x=-sqrt(13)