What is the answer to log_{6}(2x+3)=3 ?

The answer to log_{6}(2x+3)=3 is x= 213/2

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log_{6}(2x+3)=3

lo g_{6} (2 x + 3) = 3

x = \frac{213}{2}

Solution steps

lo g_{6} (2 x + 3) = 3

Apply log rules

2 x + 3 = 216

Solve

2 x + 3 = 216 : x = \frac{213}{2}

x = \frac{213}{2}

0 = ln (x - 2)

x, 5 lo g_{3} (x + 11) = 5

lo g_{\frac{1}{2}} (x) = 3 2^{0}

lo g_{6} (b) = 5

lo g_{4} (3 x + 4) + lo g_{4} (16) = 5

What is the answer to log_{6}(2x+3)=3 ?
The answer to log_{6}(2x+3)=3 is x= 213/2
Solve for x: log_{6}(2x+3)=3
The solution is x= 213/2