What is the answer to log_{2}(8x)-4log_{2}(4)=0 ?

The answer to log_{2}(8x)-4log_{2}(4)=0 is x=32

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log_{2}(8x)-4log_{2}(4)=0

lo g_{2} (8 x) - 4 lo g_{2} (4) = 0

x = 32

Solution steps

lo g_{2} (8 x) - 4 lo g_{2} (4) = 0

Move

4 lo g_{2} (4)

to the right side

lo g_{2} (8 x) = 4 lo g_{2} (4)

Apply log rules

8 x = 256

Solve

8 x = 256 : x = 32

x = 32

Verify Solutions:

x = 32

True

The solution is

x = 32

16 = - lo g_{10} (x)

4 ln (6 x) = 12

lo g_{4} (3 x + 4) = 3

lo g_{4} (3 x + 4) = 2

y, ln (y) = 9 t + 5

What is the answer to log_{2}(8x)-4log_{2}(4)=0 ?
The answer to log_{2}(8x)-4log_{2}(4)=0 is x=32
Solve for x: log_{2}(8x)-4log_{2}(4)=0
The solution is x=32