What is the answer to ln(4x)-3ln(x^2)=ln(3) ?

The answer to ln(4x)-3ln(x^2)=ln(3) is x= 1/(e^{\frac{ln(3)-2ln(2)){5}}}

Solve for x: ln(4x)-3ln(x^2)=ln(3)

The solution is x= 1/(e^{\frac{ln(3)-2ln(2)){5}}}

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ln (4 x) - 3 ln (x^{2}) = ln (3)

x = \frac{1}{e ^{\frac{l n ( 3 ) - 2 l n ( 2 )}{5}}}

Solution steps

ln (4 x) - 3 ln (x^{2}) = ln (3)

Apply log rules

x = \frac{1}{e ^{\frac{l n ( 3 ) - 2 l n ( 2 )}{5}}}

Verify Solutions:

x = \frac{1}{e ^{\frac{l n ( 3 ) - 2 l n ( 2 )}{5}}}

True

The solution is

x = \frac{1}{e ^{\frac{l n ( 3 ) - 2 l n ( 2 )}{5}}}

ln (x) + ln (x + 3) = 0

lo g_{10} (x + 5) = lo g_{10} (2 x - 3)

ln (3 x + 3.7) - 1.2 = - 12.3

ln (x) = 5.943189204

7.53 = - lo g_{10} (x)

What is the answer to ln(4x)-3ln(x^2)=ln(3) ?
The answer to ln(4x)-3ln(x^2)=ln(3) is x= 1/(e^{\frac{ln(3)-2ln(2)){5}}}
Solve for x: ln(4x)-3ln(x^2)=ln(3)
The solution is x= 1/(e^{\frac{ln(3)-2ln(2)){5}}}