What is the answer to ln(3x+3.7)-1.2=-12.3 ?

The answer to ln(3x+3.7)-1.2=-12.3 is x=(1/(e^{11.1)}-3.7)/3

Solve for x: ln(3x+3.7)-1.2=-12.3

The solution is x=(1/(e^{11.1)}-3.7)/3

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ln (3 x + 3.7) - 1.2 = - 12.3

x = \frac{\frac{1}{e ^{11.1}} - 3.7}{3}

Solution steps

ln (3 x + 3.7) - 1.2 = - 12.3

Move

1.2

to the right side

ln (3 x + 3.7) = - 11.1

Apply log rules

3 x + 3.7 = \frac{1}{e ^{11.1}}

Solve

3 x + 3.7 = \frac{1}{e ^{11.1}} : x = \frac{\frac{1}{e ^{11.1}} - 3.7}{3}

x = \frac{\frac{1}{e ^{11.1}} - 3.7}{3}

Verify Solutions:

x = \frac{\frac{1}{e ^{11.1}} - 3.7}{3}

True

The solution is

x = \frac{\frac{1}{e ^{11.1}} - 3.7}{3}

ln (x) = 5.943189204

7.53 = - lo g_{10} (x)

x ln (2 x) = 0

x, ln (x) + ln (x - 7) = 0

9 = 10 lo g_{10} (\frac{x}{1})

What is the answer to ln(3x+3.7)-1.2=-12.3 ?
The answer to ln(3x+3.7)-1.2=-12.3 is x=(1/(e^{11.1)}-3.7)/3
Solve for x: ln(3x+3.7)-1.2=-12.3
The solution is x=(1/(e^{11.1)}-3.7)/3