What is the answer to solvefor x,ln(x)+ln(x-7)=0 ?

The answer to solvefor x,ln(x)+ln(x-7)=0 is x=(7+sqrt(53))/2

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solvefor x,ln(x)+ln(x-7)=0

solve for

x, ln (x) + ln (x - 7) = 0

x = \frac{7 + 53}{2}

Solution steps

ln (x) + ln (x - 7) = 0

Apply log rules

x (x - 7) = 1

Solve

x (x - 7) = 1 : x = \frac{7 + 53}{2}, x = \frac{7 - 53}{2}

x = \frac{7 + 53}{2}, x = \frac{7 - 53}{2}

Verify Solutions:

x = \frac{7 + 53}{2}

True

, x = \frac{7 - 53}{2}

False

The solution is

x = \frac{7 + 53}{2}

9 = 10 lo g_{10} (\frac{x}{1})

lo g_{343} (x) = - \frac{1}{3}

lo g_{10} (10) + lo g_{10} (x - 9) = 1

- 3 x + 9 = lo g_{10} (x)

lo g_{2} (x + 5) - lo g_{2} (x - 5) = 3

What is the answer to solvefor x,ln(x)+ln(x-7)=0 ?
The answer to solvefor x,ln(x)+ln(x-7)=0 is x=(7+sqrt(53))/2