What is the answer to -3x+9=log_{10}(x) ?

The answer to -3x+9=log_{10}(x) is x=(\W_{0}(3000000000ln(10)))/(3ln(10))

Solve for x: -3x+9=log_{10}(x)

The solution is x=(\W_{0}(3000000000ln(10)))/(3ln(10))

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- 3 x + 9 = lo g_{10} (x)

x = \frac{W _{0} ( 3000000000 ln ( 10 ) )}{3 ln ( 10 )}

Solution steps

- 3 x + 9 = lo g_{10} (x)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

1 0^{- 3 x + 9} = 1 0^{l o g_{10} (x)}

Simplify

1 0^{l o g_{10} (x)} : x

1 0^{- 3 x + 9} = x

Solve

1 0^{- 3 x + 9} = x : x = \frac{W _{0} ( 3000000000 ln ( 10 ) )}{3 ln ( 10 )}

x = \frac{W _{0} ( 3000000000 ln ( 10 ) )}{3 ln ( 10 )}

Verify Solutions:

x = \frac{W _{0} ( 3000000000 ln ( 10 ) )}{3 ln ( 10 )}

True

The solution is

x = \frac{W _{0} ( 3000000000 ln ( 10 ) )}{3 ln ( 10 )}

lo g_{2} (x + 5) - lo g_{2} (x - 5) = 3

lo g_{4} (5 x - 4) = 2 x

lo g_{12} (4 x + 2) = 0

ln (\frac{( x + 3 )}{( x - 1 )}) = 1

lo g_{x} (4) = lo g_{10} (100)

What is the answer to -3x+9=log_{10}(x) ?
The answer to -3x+9=log_{10}(x) is x=(\W_{0}(3000000000ln(10)))/(3ln(10))
Solve for x: -3x+9=log_{10}(x)
The solution is x=(\W_{0}(3000000000ln(10)))/(3ln(10))