What is the answer to ln(((x+3))/((x-1)))=1 ?

The answer to ln(((x+3))/((x-1)))=1 is x=(e+3)/(e-1)

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ln(((x+3))/((x-1)))=1

ln (\frac{( x + 3 )}{( x - 1 )}) = 1

x = \frac{e + 3}{e - 1}

Solution steps

ln (\frac{( x + 3 )}{( x - 1 )}) = 1

Apply log rules

\frac{x + 3}{x - 1} = e^{1}

Multiply both sides by

x - 1

\frac{x + 3}{x - 1} (x - 1) = e^{1} (x - 1)

Simplify

x + 3 = e (x - 1)

Solve

x + 3 = e (x - 1) : x = \frac{e + 3}{e - 1}

x = \frac{e + 3}{e - 1}

Verify Solutions:

x = \frac{e + 3}{e - 1}

True

The solution is

x = \frac{e + 3}{e - 1}

lo g_{x} (4) = lo g_{10} (100)

lo g_{5} (x + 5) + lo g_{5} (x - 4) = 3

lo g_{3} (x) = x

lo g_{3} (x) = a

x, y - ln (x + 1) = 0

What is the answer to ln(((x+3))/((x-1)))=1 ?
The answer to ln(((x+3))/((x-1)))=1 is x=(e+3)/(e-1)
Solve for x: ln(((x+3))/((x-1)))=1
The solution is x=(e+3)/(e-1)