What is the answer to 2log_{10}(x-1)=log_{10}(x+1) ?

The answer to 2log_{10}(x-1)=log_{10}(x+1) is x=3

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2log_{10}(x-1)=log_{10}(x+1)

2 lo g_{10} (x - 1) = lo g_{10} (x + 1)

x = 3

Solution steps

2 lo g_{10} (x - 1) = lo g_{10} (x + 1)

Apply log rules

(x - 1)^{2} = x + 1

Solve

(x - 1)^{2} = x + 1 : x = 3, x = 0

x = 3, x = 0

Verify Solutions:

x = 3

True

, x = 0

False

The solution is

x = 3

ln (x - 4) + ln (7) = ln (x) + 2 ln (3)

lo g_{2} (x) + 2 lo g_{2} (3) = 1

3.2 = - lo g_{10} (x)

lo g_{10} (x) = - 4.1

6 ln (2 x + 10) - 4 = 8

What is the answer to 2log_{10}(x-1)=log_{10}(x+1) ?
The answer to 2log_{10}(x-1)=log_{10}(x+1) is x=3
Solve for x: 2log_{10}(x-1)=log_{10}(x+1)
The solution is x=3