What is the answer to solvefor y,-ln(x-3)=ln(y+2) ?

The answer to solvefor y,-ln(x-3)=ln(y+2) is y= 1/(x-3)-2

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solvefor y,-ln(x-3)=ln(y+2)

solve for

y, - ln (x - 3) = ln (y + 2)

y = \frac{1}{x - 3} - 2

Solution steps

- ln (x - 3) = ln (y + 2)

Apply log rules

\frac{1}{x - 3} = y + 2

Solve

\frac{1}{x - 3} = y + 2 : y = \frac{1}{x - 3} - 2

y = \frac{1}{x - 3} - 2

4 ln (5 x + 1) + 3 = 15

lo g_{5} (x) = 3 - 2 lo g_{x} (5)

16 ln (x) = \frac{1}{ln ( x )}

lo g_{3} (- 2 x - 10) = 2 + lo g_{3} (6)

1.23 = \frac{0.0257}{4} ln (k)

What is the answer to solvefor y,-ln(x-3)=ln(y+2) ?
The answer to solvefor y,-ln(x-3)=ln(y+2) is y= 1/(x-3)-2