What is the answer to log_{3}(-2x-10)=2+log_{3}(6) ?

The answer to log_{3}(-2x-10)=2+log_{3}(6) is x=-32

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log_{3}(-2x-10)=2+log_{3}(6)

lo g_{3} (- 2 x - 10) = 2 + lo g_{3} (6)

x = - 32

Solution steps

lo g_{3} (- 2 x - 10) = 2 + lo g_{3} (6)

Apply log rules

- 2 x - 10 = 54

Solve

- 2 x - 10 = 54 : x = - 32

x = - 32

1.23 = \frac{0.0257}{4} ln (k)

x, ln (2 x + 1) = 2 - ln (x)

lo g_{10} (x - 2) = 1.258

ln (x) = ln (2 x - 3)

lo g_{7} (10 x) + 20 = 0

What is the answer to log_{3}(-2x-10)=2+log_{3}(6) ?
The answer to log_{3}(-2x-10)=2+log_{3}(6) is x=-32
Solve for x: log_{3}(-2x-10)=2+log_{3}(6)
The solution is x=-32