What is the answer to 1/8 x=log_{2}(x) ?

The answer to 1/8 x=log_{2}(x) is x=-(8\W_{-1}(-(ln(2))/8))/(ln(2)),x=-(8\W_{0}(-(ln(2))/8))/(ln(2))

Solve for x: 1/8 x=log_{2}(x)

The solution is x=-(8\W_{-1}(-(ln(2))/8))/(ln(2)),x=-(8\W_{0}(-(ln(2))/8))/(ln(2))

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\frac{1}{8} x = lo g_{2} (x)

x = - \frac{8 W _{- 1} ( - \frac{l n ( 2 )}{8} )}{ln ( 2 )}, x = - \frac{8 W _{0} ( - \frac{l n ( 2 )}{8} )}{ln ( 2 )}

Solution steps

\frac{1}{8} x = lo g_{2} (x)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

2^{\frac{1}{8} x} = 2^{l o g_{2} (x)}

Simplify

2^{l o g_{2} (x)} : x

2^{\frac{1}{8} x} = x

Solve

2^{\frac{1}{8} x} = x : x = - \frac{8 W _{- 1} ( - \frac{l n ( 2 )}{8} )}{ln ( 2 )}, x = - \frac{8 W _{0} ( - \frac{l n ( 2 )}{8} )}{ln ( 2 )}

x = - \frac{8 W _{- 1} ( - \frac{l n ( 2 )}{8} )}{ln ( 2 )}, x = - \frac{8 W _{0} ( - \frac{l n ( 2 )}{8} )}{ln ( 2 )}

Verify Solutions:

x = - \frac{8 W _{- 1} ( - \frac{l n ( 2 )}{8} )}{ln ( 2 )}

True

, x = - \frac{8 W _{0} ( - \frac{l n ( 2 )}{8} )}{ln ( 2 )}

True

The solutions are

x = - \frac{8 W _{- 1} ( - \frac{l n ( 2 )}{8} )}{ln ( 2 )}, x = - \frac{8 W _{0} ( - \frac{l n ( 2 )}{8} )}{ln ( 2 )}

(2 x) (ln (x)) - x = 0

x, lo g_{x} (3 x - y) = 2

lo g_{3} (5 x) = 4

lo g_{2} (x) + lo g_{4} (x^{2}) = 4

1 + lo g_{10} (3 x - 4) = 0

What is the answer to 1/8 x=log_{2}(x) ?
The answer to 1/8 x=log_{2}(x) is x=-(8\W_{-1}(-(ln(2))/8))/(ln(2)),x=-(8\W_{0}(-(ln(2))/8))/(ln(2))
Solve for x: 1/8 x=log_{2}(x)
The solution is x=-(8\W_{-1}(-(ln(2))/8))/(ln(2)),x=-(8\W_{0}(-(ln(2))/8))/(ln(2))