What is the answer to log_{10}(z)+12=9 ?

The answer to log_{10}(z)+12=9 is z= 1/1000

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log_{10}(z)+12=9

lo g_{10} (z) + 12 = 9

z = \frac{1}{1000}

Decimal Notation

z = 0.001

Solution steps

lo g_{10} (z) + 12 = 9

Move

12

to the right side

lo g_{10} (z) = - 3

Apply log rules

z = \frac{1}{1000}

Verify Solutions:

z = \frac{1}{1000}

True

The solution is

z = \frac{1}{1000}

x, ln (y) = ln (x + 1)

x = 1 + 3.322 (lo g_{28} (x))

lo g_{10} (x) = 1.97 - 1.32

x, ln (y) = ln (x + 2)

lo g_{5} (a + 3) = 1 - lo g_{5} (a - 1)

What is the answer to log_{10}(z)+12=9 ?
The answer to log_{10}(z)+12=9 is z= 1/1000
Solve for z: log_{10}(z)+12=9
The solution is z= 1/1000