What are the solutions to the equation 10w(w-2)+10=0 ?

The solutions to the equation 10w(w-2)+10=0 are w=1

Find the zeros of 10w(w-2)+10=0

The zeros of 10w(w-2)+10=0 are w=1

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10 w (w - 2) + 10 = 0

w = 1

Solution steps

10 w (w - 2) + 10 = 0

Expand

10 w (w - 2) + 10 : 10 w^{2} - 20 w + 10

10 w^{2} - 20 w + 10 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 10 \cdot 10}{2 \cdot 10}

(- 20)^{2} - 4 \cdot 10 \cdot 10 = 0

w_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 10}

w = \frac{- ( - 20 )}{2 \cdot 10}

\frac{- ( - 20 )}{2 \cdot 10} = 1

w = 1

The solution to the quadratic equation is:

w = 1

x - 4 \geq 17

1 + \frac{2 x}{7} - \frac{1}{2} (x + 7) \geq x

∣ x - 3 ∣ = 3 x + 5

\frac{45 x ^{2}}{60 x ^{2} y}

\frac{3 ^{8}}{6 ^{8}}

What are the solutions to the equation 10w(w-2)+10=0 ?
The solutions to the equation 10w(w-2)+10=0 are w=1
Find the zeros of 10w(w-2)+10=0
The zeros of 10w(w-2)+10=0 are w=1