What is the answer to log_{3}((r+4)^2)=2 ?

The answer to log_{3}((r+4)^2)=2 is r=-1,r=-7

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log_{3}((r+4)^2)=2

lo g_{3} ((r + 4)^{2}) = 2

r = - 1, r = - 7

Solution steps

lo g_{3} ((r + 4)^{2}) = 2

Apply log rules

(r + 4)^{2} = 9

Solve

(r + 4)^{2} = 9 : r = - 1, r = - 7

r = - 1, r = - 7

1 \cdot 15 = lo g_{10} (x)

lo g_{4} (x) + lo g_{2} (x) = 12

lo g_{10} (x) = - 2.9

lo g_{10} (x) = - 2.8

lo g_{10} (E) = 11.8 + 1.5 (7)

What is the answer to log_{3}((r+4)^2)=2 ?
The answer to log_{3}((r+4)^2)=2 is r=-1,r=-7
Solve for r: log_{3}((r+4)^2)=2
The solution is r=-1,r=-7