What is the answer to log_{10}(x)-log_{10}(x+1)=1 ?

The answer to log_{10}(x)-log_{10}(x+1)=1 is No Solution for x\in\mathbb{R}

Solve for x: log_{10}(x)-log_{10}(x+1)=1

The solution is No Solution for x\in\mathbb{R}

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lo g_{10} (x) - lo g_{10} (x + 1) = 1

No Solution for x \in R

Solution steps

lo g_{10} (x) - lo g_{10} (x + 1) = 1

Add

lo g_{10} (x + 1)

to both sides

lo g_{10} (x) - lo g_{10} (x + 1) + lo g_{10} (x + 1) = 1 + lo g_{10} (x + 1)

Simplify

lo g_{10} (x) = 1 + lo g_{10} (x + 1)

Apply log rules

x = 10 (x + 1)

Solve

x = 10 (x + 1) : x = - \frac{10}{9}

x = - \frac{10}{9}

Verify Solutions:

x = - \frac{10}{9}

False

The solution is

No Solution for x \in R

10 = \frac{ln ( 2 )}{ln ( 1 + x )}

ln (x) = 7, ln (\frac{x}{e})

3 ln (x) = ln (x^{3})

lo g_{10} (x) = - 1.9

lo g_{10} (x) = - 1.4

What is the answer to log_{10}(x)-log_{10}(x+1)=1 ?
The answer to log_{10}(x)-log_{10}(x+1)=1 is No Solution for x\in\mathbb{R}
Solve for x: log_{10}(x)-log_{10}(x+1)=1
The solution is No Solution for x\in\mathbb{R}