What is the answer to ln(x)+ln(5x)=2 ?

The answer to ln(x)+ln(5x)=2 is x=e^{(2-ln(5))/2}

Solve for x: ln(x)+ln(5x)=2

The solution is x=e^{(2-ln(5))/2}

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ln (x) + ln (5 x) = 2

x = e^{\frac{2 - l n ( 5 )}{2}}

Decimal Notation

x = 1.21565 \dots

Solution steps

ln (x) + ln (5 x) = 2

Apply log rules

x = e^{\frac{2 - l n ( 5 )}{2}}

Verify Solutions:

x = e^{\frac{2 - l n ( 5 )}{2}}

True

The solution is

x = e^{\frac{2 - l n ( 5 )}{2}}

lo g_{3} (x^{2} + 4 x + 12) = 2

lo g_{2} (x) + lo g_{2} (x) = 4

ln (4 x) + ln (8 x) = 1

P, lo g_{- 1} (P) = n

lo g_{729} (x) = - \frac{5}{6}

What is the answer to ln(x)+ln(5x)=2 ?
The answer to ln(x)+ln(5x)=2 is x=e^{(2-ln(5))/2}
Solve for x: ln(x)+ln(5x)=2
The solution is x=e^{(2-ln(5))/2}