What is the answer to log_{2}(x)+log_{2}(4x)=4 ?

The answer to log_{2}(x)+log_{2}(4x)=4 is x=2

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log_{2}(x)+log_{2}(4x)=4

lo g_{2} (x) + lo g_{2} (4 x) = 4

x = 2

Solution steps

lo g_{2} (x) + lo g_{2} (4 x) = 4

Apply log rules

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{x} (18) = 7.01

12 = lo g_{5} (x + 150) + 9

\frac{x ln ( x + 3 )}{x ^{2} + 1} = 0

lo g_{9} (a) = 12

ln (x) = 3 + ln (x - 2)

What is the answer to log_{2}(x)+log_{2}(4x)=4 ?
The answer to log_{2}(x)+log_{2}(4x)=4 is x=2
Solve for x: log_{2}(x)+log_{2}(4x)=4
The solution is x=2