What is the answer to ln(x)=3+ln(x-2) ?

The answer to ln(x)=3+ln(x-2) is x=(2e^3)/(e^3-1)

Solve for x: ln(x)=3+ln(x-2)

The solution is x=(2e^3)/(e^3-1)

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ln (x) = 3 + ln (x - 2)

x = \frac{2 e ^{3}}{e ^{3} - 1}

Decimal Notation

x = 2.10479 \dots

Solution steps

ln (x) = 3 + ln (x - 2)

Apply log rules

x = e^{3} (x - 2)

Solve

x = e^{3} (x - 2) : x = \frac{2 e ^{3}}{e ^{3} - 1}

x = \frac{2 e ^{3}}{e ^{3} - 1}

Verify Solutions:

x = \frac{2 e ^{3}}{e ^{3} - 1}

True

The solution is

x = \frac{2 e ^{3}}{e ^{3} - 1}

ln (X - 2 X^{2}) - ln (4) = 0

e^{l n (2)} = lo g_{- x} (25)

2 lo g_{2} (x - 3) = 2

- lo g_{10} (x) = 5.05

lo g_{2} (3 x^{2} - 23 x) = 3

What is the answer to ln(x)=3+ln(x-2) ?
The answer to ln(x)=3+ln(x-2) is x=(2e^3)/(e^3-1)
Solve for x: ln(x)=3+ln(x-2)
The solution is x=(2e^3)/(e^3-1)