What is the answer to e^{ln(2)}=log_{-x}(25) ?

The answer to e^{ln(2)}=log_{-x}(25) is x=-5

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e^{ln(2)}=log_{-x}(25)

e^{l n (2)} = lo g_{- x} (25)

x = - 5

Solution steps

e^{l n (2)} = lo g_{- x} (25)

Apply log rules

e^{l n (2)} = \frac{1}{lo g _{25} ( - x )}

Multiply both sides by

lo g_{25} (- x)

e^{l n (2)} lo g_{25} (- x) = \frac{1}{lo g _{25} ( - x )} lo g_{25} (- x)

Apply log rules

- x = 5

Solve

- x = 5 : x = - 5

x = - 5

Verify Solutions:

x = - 5

True

The solution is

x = - 5

2 lo g_{2} (x - 3) = 2

- lo g_{10} (x) = 5.05

lo g_{2} (3 x^{2} - 23 x) = 3

lo g_{10} (X) = 4.6184

lo g_{2} (2 x + 3) + lo g_{2} (x - 2) = 2

What is the answer to e^{ln(2)}=log_{-x}(25) ?
The answer to e^{ln(2)}=log_{-x}(25) is x=-5