What is the answer to log_{2}(3x^2-23x)=3 ?

The answer to log_{2}(3x^2-23x)=3 is x=8,x=-1/3

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log_{2}(3x^2-23x)=3

lo g_{2} (3 x^{2} - 23 x) = 3

x = 8, x = - \frac{1}{3}

Decimal Notation

x = 8, x = - 0.33333 \dots

Solution steps

lo g_{2} (3 x^{2} - 23 x) = 3

Apply log rules

3 x^{2} - 23 x = 8

Solve

3 x^{2} - 23 x = 8 : x = 8, x = - \frac{1}{3}

x = 8, x = - \frac{1}{3}

lo g_{10} (X) = 4.6184

lo g_{2} (2 x + 3) + lo g_{2} (x - 2) = 2

4 ln (x - 3) = - 4

2 lo g_{3} (6) = lo g_{3} (x - 5)

lo g_{2} (2 p + 1) = lo g_{2} (5 p - 2)

What is the answer to log_{2}(3x^2-23x)=3 ?
The answer to log_{2}(3x^2-23x)=3 is x=8,x=-1/3
Solve for x: log_{2}(3x^2-23x)=3
The solution is x=8,x=-1/3