What is the answer to 2log_{3}(6)=log_{3}(x-5) ?

The answer to 2log_{3}(6)=log_{3}(x-5) is x=41

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2log_{3}(6)=log_{3}(x-5)

2 lo g_{3} (6) = lo g_{3} (x - 5)

x = 41

Solution steps

2 lo g_{3} (6) = lo g_{3} (x - 5)

Apply log rules

36 = x - 5

Solve

36 = x - 5 : x = 41

x = 41

Verify Solutions:

x = 41

True

The solution is

x = 41

lo g_{2} (2 p + 1) = lo g_{2} (5 p - 2)

ln (x^{2}) - ln (x) - ln (4) = 0

lo g_{20} (x) + lo g_{20} (x - 1) = 1

lo g_{10} (10 x) = 3.22

lo g_{10} (x) = - 4.703389

What is the answer to 2log_{3}(6)=log_{3}(x-5) ?
The answer to 2log_{3}(6)=log_{3}(x-5) is x=41
Solve for x: 2log_{3}(6)=log_{3}(x-5)
The solution is x=41