What is the answer to log_{2}(3x-1)=4 ?

The answer to log_{2}(3x-1)=4 is x= 17/3

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log_{2}(3x-1)=4

lo g_{2} (3 x - 1) = 4

x = \frac{17}{3}

Decimal Notation

x = 5.66666 \dots

Solution steps

lo g_{2} (3 x - 1) = 4

Apply log rules

3 x - 1 = 16

Solve

3 x - 1 = 16 : x = \frac{17}{3}

x = \frac{17}{3}

lo g_{2} (3 x - 1) = 5

lo g_{2} (3 x - 1) = 2

ln (\frac{3}{2} + C) = 0

lo g_{0.5} (x) = lo g_{2} (5)

lo g_{3} (- x - 1) - lo g_{3} (5 x) = - 3

What is the answer to log_{2}(3x-1)=4 ?
The answer to log_{2}(3x-1)=4 is x= 17/3
Solve for x: log_{2}(3x-1)=4
The solution is x= 17/3