What is the answer to log_{2}(3-x)+log_{2}(-x)=2 ?

The answer to log_{2}(3-x)+log_{2}(-x)=2 is x=-1

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log_{2}(3-x)+log_{2}(-x)=2

lo g_{2} (3 - x) + lo g_{2} (- x) = 2

x = - 1

Solution steps

lo g_{2} (3 - x) + lo g_{2} (- x) = 2

Apply log rules

- x (3 - x) = 4

Solve

- x (3 - x) = 4 : x = 4, x = - 1

x = 4, x = - 1

Verify Solutions:

x = 4

False

, x = - 1

True

The solution is

x = - 1

lo g_{b} (9) = - \frac{1}{3}

- lo g_{10} (x) = 2.8

- lo g_{10} (x) = 2.1

ln (5 - 2 x) = - 7

ln (5 - 2 x) = - 5

What is the answer to log_{2}(3-x)+log_{2}(-x)=2 ?
The answer to log_{2}(3-x)+log_{2}(-x)=2 is x=-1
Solve for x: log_{2}(3-x)+log_{2}(-x)=2
The solution is x=-1