What is the answer to log_{3}((r+7)^2)=4 ?

The answer to log_{3}((r+7)^2)=4 is r=2,r=-16

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log_{3}((r+7)^2)=4

lo g_{3} ((r + 7)^{2}) = 4

r = 2, r = - 16

Solution steps

lo g_{3} ((r + 7)^{2}) = 4

Apply log rules

(r + 7)^{2} = 81

Solve

(r + 7)^{2} = 81 : r = 2, r = - 16

r = 2, r = - 16

- 10 ln (2 p) = 40

10 lo g_{10} (x^{2}) = - 10

lo g_{10} (x^{2} + 48 x) = 1

ln (x - 1) + ln (x) = 1

ln (C) = 0

What is the answer to log_{3}((r+7)^2)=4 ?
The answer to log_{3}((r+7)^2)=4 is r=2,r=-16
Solve for r: log_{3}((r+7)^2)=4
The solution is r=2,r=-16