What is the answer to log_{10}(x)+log_{10}(x+4)=7 ?

The answer to log_{10}(x)+log_{10}(x+4)=7 is x=2(sqrt(2500001)-1)

Solve for x: log_{10}(x)+log_{10}(x+4)=7

The solution is x=2(sqrt(2500001)-1)

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lo g_{10} (x) + lo g_{10} (x + 4) = 7

x = 2 (2500001 - 1)

Decimal Notation

x = 3160.27829 \dots

Solution steps

lo g_{10} (x) + lo g_{10} (x + 4) = 7

Apply log rules

x (x + 4) = 10000000

Solve

x (x + 4) = 10000000 : x = 2 (2500001 - 1), x = - 2 (1 + 2500001)

x = 2 (2500001 - 1), x = - 2 (1 + 2500001)

Verify Solutions:

x = 2 (2500001 - 1)

True

, x = - 2 (1 + 2500001)

False

The solution is

x = 2 (2500001 - 1)

2 ln (x) - ln (x + 6) = 3 ln^{2} (x)

4 lo g_{5} (2) = lo g_{5} (x)

lo g_{10} (x) + lo g_{10} (x - 8) = 2

- lo g_{10} (x) = 7.8

lo g_{6} (x + 7) + lo g_{6} (x + 2) = 2

What is the answer to log_{10}(x)+log_{10}(x+4)=7 ?
The answer to log_{10}(x)+log_{10}(x+4)=7 is x=2(sqrt(2500001)-1)
Solve for x: log_{10}(x)+log_{10}(x+4)=7
The solution is x=2(sqrt(2500001)-1)