What is the answer to solvefor x,e^y=y+ln(x) ?

The answer to solvefor x,e^y=y+ln(x) is x=e^{e^y-y}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,e^y=y+ln(x)

solve for

x, e^{y} = y + ln (x)

x = e^{e^{y} - y}

Solution steps

e^{y} = y + ln (x)

Switch sides

y + ln (x) = e^{y}

Move

y

to the right side

ln (x) = e^{y} - y

Apply log rules

x = e^{e^{y} - y}

Verify Solutions:

x = e^{e^{y} - y}

True

The solution is

x = e^{e^{y} - y}

ln (3^{x + 1}) = ln (2^{x})

- lo g_{10} (x) = 4.4

lo g_{a} (0) = 1

ln (x - 3) + ln (x + 4) = 3 ln (2)

b (x) = ln (x) - 4

What is the answer to solvefor x,e^y=y+ln(x) ?
The answer to solvefor x,e^y=y+ln(x) is x=e^{e^y-y}