What is the answer to ln(3^{x+1})=ln(2^x) ?

The answer to ln(3^{x+1})=ln(2^x) is x=-(ln(3))/(ln(3)-ln(2))

Solve for x: ln(3^{x+1})=ln(2^x)

The solution is x=-(ln(3))/(ln(3)-ln(2))

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ln (3^{x + 1}) = ln (2^{x})

x = - \frac{ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = - 2.70951 \dots

Solution steps

ln (3^{x + 1}) = ln (2^{x})

Apply log rules

3^{x + 1} = 2^{x}

Solve

3^{x + 1} = 2^{x} : x = - \frac{ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

x = - \frac{ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

Verify Solutions:

x = - \frac{ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

True

The solution is

x = - \frac{ln ( 3 )}{ln ( 3 ) - ln ( 2 )}

- lo g_{10} (x) = 4.4

lo g_{a} (0) = 1

ln (x - 3) + ln (x + 4) = 3 ln (2)

b (x) = ln (x) - 4

lo g_{4} (x) + lo g_{4} (x + 12) = 3

What is the answer to ln(3^{x+1})=ln(2^x) ?
The answer to ln(3^{x+1})=ln(2^x) is x=-(ln(3))/(ln(3)-ln(2))
Solve for x: ln(3^{x+1})=ln(2^x)
The solution is x=-(ln(3))/(ln(3)-ln(2))