What is the answer to log_{3}(4x)+log_{3}(5)=2 ?

The answer to log_{3}(4x)+log_{3}(5)=2 is x= 9/20

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log_{3}(4x)+log_{3}(5)=2

lo g_{3} (4 x) + lo g_{3} (5) = 2

x = \frac{9}{20}

Decimal Notation

x = 0.45

Solution steps

lo g_{3} (4 x) + lo g_{3} (5) = 2

Move

lo g_{3} (5)

to the right side

lo g_{3} (4 x) = 2 - lo g_{3} (5)

Apply log rules

4 x = \frac{9}{5}

Solve

4 x = \frac{9}{5} : x = \frac{9}{20}

x = \frac{9}{20}

Verify Solutions:

x = \frac{9}{20}

True

The solution is

x = \frac{9}{20}

e^{l n (2 x)} = 2 x

lo g_{3} (x) = 6

lo g_{4} (x + 12) + lo g_{4} (x) = 3

8 lo g_{2} (x + 1) = 40

ln (x) + ln (x - 5) = ln (7 x)

What is the answer to log_{3}(4x)+log_{3}(5)=2 ?
The answer to log_{3}(4x)+log_{3}(5)=2 is x= 9/20
Solve for x: log_{3}(4x)+log_{3}(5)=2
The solution is x= 9/20