What is the answer to log_{6}((3x)/(x+1))=1 ?

The answer to log_{6}((3x)/(x+1))=1 is x=-2

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log_{6}((3x)/(x+1))=1

lo g_{6} (\frac{3 x}{x + 1}) = 1

x = - 2

Solution steps

lo g_{6} (\frac{3 x}{x + 1}) = 1

Apply log rules

\frac{3 x}{x + 1} = 6^{1}

Multiply both sides by

x + 1

\frac{3 x}{x + 1} (x + 1) = 6^{1} (x + 1)

Simplify

3 x = 6 (x + 1)

Solve

3 x = 6 (x + 1) : x = - 2

x = - 2

Verify Solutions:

x = - 2

True

The solution is

x = - 2

lo g_{6} (x^{2} - x) = 1

lo g_{2} (x) = \frac{1}{x}

lo g_{x + 3} (9) = 3

j (x) = \frac{x}{ln ( x )}

- lo g_{10} (x) = 0.05

What is the answer to log_{6}((3x)/(x+1))=1 ?
The answer to log_{6}((3x)/(x+1))=1 is x=-2
Solve for x: log_{6}((3x)/(x+1))=1
The solution is x=-2