What is the answer to log_{6}(x+1)=1-log_{6}(2) ?

The answer to log_{6}(x+1)=1-log_{6}(2) is x=2

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log_{6}(x+1)=1-log_{6}(2)

lo g_{6} (x + 1) = 1 - lo g_{6} (2)

x = 2

Solution steps

lo g_{6} (x + 1) = 1 - lo g_{6} (2)

Apply log rules

x + 1 = 3

Solve

x + 1 = 3 : x = 2

x = 2

(lo g_{e} (x) - 1)^{2} = 4

n - 8 lo g_{2} (n) = 0

lo g_{2} (72 x) - lo g_{2} (x + 96) = 3

lo g_{4} (y) = 1

ln (x) + ln (2 x) = ln (450)

What is the answer to log_{6}(x+1)=1-log_{6}(2) ?
The answer to log_{6}(x+1)=1-log_{6}(2) is x=2
Solve for x: log_{6}(x+1)=1-log_{6}(2)
The solution is x=2