What is the answer to log_{2}(72x)-log_{2}(x+96)=3 ?

The answer to log_{2}(72x)-log_{2}(x+96)=3 is x=12

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log_{2}(72x)-log_{2}(x+96)=3

lo g_{2} (72 x) - lo g_{2} (x + 96) = 3

x = 12

Solution steps

lo g_{2} (72 x) - lo g_{2} (x + 96) = 3

Add

lo g_{2} (x + 96)

to both sides

lo g_{2} (72 x) - lo g_{2} (x + 96) + lo g_{2} (x + 96) = 3 + lo g_{2} (x + 96)

Simplify

lo g_{2} (72 x) = 3 + lo g_{2} (x + 96)

Apply log rules

72 x = 8 (x + 96)

Solve

72 x = 8 (x + 96) : x = 12

x = 12

Verify Solutions:

x = 12

True

The solution is

x = 12

lo g_{4} (y) = 1

ln (x) + ln (2 x) = ln (450)

- 4 lo g_{2} (5 x) = 12

4 lo g_{4} (x) = lo g_{2} (x + 5) + 4

ln (x) + ln (x - 2) - ln (x + 4) = 0

What is the answer to log_{2}(72x)-log_{2}(x+96)=3 ?
The answer to log_{2}(72x)-log_{2}(x+96)=3 is x=12
Solve for x: log_{2}(72x)-log_{2}(x+96)=3
The solution is x=12