What is the answer to 4log_{4}(x)=log_{2}(x+5)+4 ?

The answer to 4log_{4}(x)=log_{2}(x+5)+4 is x=20

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4log_{4}(x)=log_{2}(x+5)+4

4 lo g_{4} (x) = lo g_{2} (x + 5) + 4

x = 20

Solution steps

4 lo g_{4} (x) = lo g_{2} (x + 5) + 4

Apply log rules

x^{2} = (x + 5) \cdot 16

Solve

x^{2} = (x + 5) \cdot 16 : x = 20, x = - 4

x = 20, x = - 4

Verify Solutions:

x = 20

True

, x = - 4

False

The solution is

x = 20

ln (x) + ln (x - 2) - ln (x + 4) = 0

8 = ln (x)

- x = ln (2 x)

lo g_{3} (x + 4) = - 3

x, ln (x^{2} - y^{2}) = 0

What is the answer to 4log_{4}(x)=log_{2}(x+5)+4 ?
The answer to 4log_{4}(x)=log_{2}(x+5)+4 is x=20
Solve for x: 4log_{4}(x)=log_{2}(x+5)+4
The solution is x=20